benchmarkfcns.multiobjective.cf8

benchmarkfcns.multiobjective.cf8(x: Annotated[numpy.typing.NDArray[numpy.float64], '[m, n]', 'flags.c_contiguous'], return_constraints: bool = False) → Annotated[numpy.typing.NDArray[numpy.float64], '[m, n]']

Computes the value of the CEC 2009 CF8 constrained multi-objective benchmark function. SCORES = multiobjective.cf8(X) computes the value of the CF8 function at point X. multiobjective.cf8 accepts a matrix of size M-by-N and returns a matrix SCORES of size M-by-3. If return_constraints is True, returns an M-by-4 matrix where the last column contains the constraint violation (values > 0 are violations). Properties:

• Recommended domain: x1, x2 in [0, 1], xj in [-2, 2] for j=3..N

Mathematical Definition

\[\begin{aligned}\]

f_1(textbf{x}) &= cos(0.5x_1pi) cos(0.5x_2pi) + frac{2}{|J_1|} sum_{j in J_1} (x_j - 2x_2 sin(2pi x_1 + frac{jpi}{n}))^2 \ f_2(textbf{x}) &= cos(0.5x_1pi) sin(0.5x_2pi) + frac{2}{|J_2|} sum_{j in J_2} (x_j - 2x_2 sin(2pi x_1 + frac{jpi}{n}))^2 \ f_3(textbf{x}) &= sin(0.5x_1pi) + frac{2}{|J_3|} sum_{j in J_3} (x_j - 2x_2 sin(2pi x_1 + frac{jpi}{n}))^2 \ text{Subject to: } & f_1^2 + f_2^2 + f_3^2 - a |\sin(N\pi(f_1^2 + f_2^2 - f_3^2 + 1))| - 1 ge 0 \ & x_1, x_2 in [0, 1], x_j in [-4, 4], quad N=2, a=4 end{aligned}

Visualization

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